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Configuration = 43
cycles = (10 5 1 7 2)(9 6 3 8 4)

a = 4, b = 6, c = 8
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cycles = (10 7 1 5 2)(9 4)(8 3)(6)

a = 1, b = 5, c = 7
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cycles = (10 7 4)(9 6)(8 5)(3)(2)(1)

a = 6, b = 8, c = 9
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cycles = (10 8 4)(9 5 6)(7)(3)(2)(1)

a = 5, b = 6, c = 9
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cycles = (10 7 4)(9)(8)(6)(5)(3)(2)(1)